Question

rationalize the denominatior 2÷√3+√5​

Answer 1

Answer:

-√3+√5

Step-by-step explanation:

Answer 2

Answer:

$\frac{2}{ \sqrt{3} + \sqrt{5} }$

$\frac{2}{ \sqrt[]{3} + \sqrt{5} } \times \frac{ \sqrt{3} - \sqrt{5} }{ \sqrt{3 } - \sqrt{5} }$

As (a+b)×(a-b)=(a×a)-(b×b),

$\frac{2( \sqrt{3} - \sqrt{5} ) }{ ({ \sqrt{3} })^{2} - {( \sqrt[]{5}) }^{2} }$

$\frac{2 \sqrt{3} - 2 \sqrt{5} }{3 - 5}$

$\frac{2 \sqrt{3} - 2 \sqrt{5} }{ - 2}$

Hence Proved.