Math, asked by niveshjain2006, 4 months ago

rationalize the denominator 1/√11-3​

Answers

Answered by ad0308
3

Answer:

1/√11-3×√11+3/√11+3

√11+3/√11-9

√11+3/2

Answered by Anonymous
11

\huge\underline\mathcal\color{purple}{AnSWeR}

 =  \frac{1}{ \sqrt{11} - 3 }

 =  \frac{1}{ \sqrt{11}  - 3}  \times  \frac{ \sqrt{11} + 3 }{ \sqrt{11}  + 3}

 =  \frac{ \sqrt{11} + 3 }{ ( { \sqrt{11} )}^{2} -  {3}^{2}  }

  =\frac{ \sqrt{11} + 3 }{11 - 9}

 =  \frac{ \sqrt{11} + 3 }{2}

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