Question

Rationalize the denominator 1/2+√3+√7..CBSE class 9​

Answer 1

Answer:

1/2+√3+√7*2+√3-√7/2+√3-√7

Step-by-step explanation:

just solve it

change the +√7 singn into-√7 and multiply numerator and denominator and solve it

Answer 2

$= > \frac{1}{2 + ( \sqrt{3 + \sqrt{7} )} }$

$= > \frac{1}{2 + ( \sqrt{3} + \sqrt{7}) \: } \times \frac{2 + ( \sqrt{3 } - \sqrt{7} )}{2 + ( \sqrt{3} - \sqrt{7} )}$

$= > \frac{2 + ( \sqrt{3} - \sqrt{7}) }{ {2}^{2} + ( { \sqrt{3} - \sqrt{7}) }^{2} }$

$= > \frac{2 + ( \sqrt{3} - \sqrt{7} ) }{4 + ( { \sqrt{3}) }^{2} - ( { \sqrt{7}) }^{2} }$

$= > \frac{2 + ( \sqrt{3} - \sqrt{7}) }{4 + 3 - 7}$

$= > \frac{2 \: + \: ( \sqrt{3} \: - \: \sqrt{7} )}{0}$

===> 2 + (√3 - √7) ✔️