Question

rationalize the denominator 1/(√3+1)​

Answer 1

Answer:

$\frac{1}{ \sqrt{3} + 1 } = \frac{1}{ \sqrt{3} + 1 } \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1 } \\ = = > \frac{ \sqrt{3} - 1}{ { \sqrt{3} }^{2} - {1}^{2} } \\ = = > \frac{ \sqrt{3} - 1 }{3 - 1} = \frac{ \sqrt{3} - 1}{2}$

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