Question

Rationalize the denominator 1 / 3 + √3​

Answer 1

Answer:

Step-by-step explanation:

$\frac{1}{3+ \sqrt{3} } = \frac{1}{3+ \sqrt{3} }$ × $\frac{3-\sqrt{3} }{3-\sqrt{3} }$

$\frac{3-\sqrt{3} }{3-\sqrt{3} }$ This basically means 1.

Now the numerator is $3 -\sqrt{3}$.

Now you know that (a+b)(a-b) = $a^{2} -b^{2}$

So now put the value of 3 in a and $\sqrt{3}$ in b.

So we get,

9 - $\sqrt{3}$ × $\sqrt{3}$=

9 - 3 = 6

So we get,

$\frac{3 -\sqrt{3}}{6}$

So now the numerator is rationlised