Question

Rationalize the denominator:
1/3+√5-2√2

Answer 1

Hi mate,

hope this solution helps.

Answer 2

Answer:$\frac{(3\sqrt{5}+3\sqrt{5}+2\sqrt{30} )}{30}$

Rationalization:
The elimination of radicals from an algebraic fraction's denominator is known as root rationalization in elementary algebra.

Solution:

$\frac{1}{\sqrt{5}+\sqrt{3} -2\sqrt{2} }$

$=\frac{(1)(\sqrt{5}+\sqrt{3}+2\sqrt{2} )}{(\sqrt{5}+\sqrt{3})^{2} -(2\sqrt{2})^{2} }$

$=\frac{(1)(\sqrt{5}+\sqrt{3}+2\sqrt{2} )}{2\sqrt{15} }$

$=\frac{(\sqrt{5}+\sqrt{3}+2\sqrt{2} )(\sqrt{15}) }{2\sqrt{15}(\sqrt{15}) }$

$=\frac{(\sqrt{45}+\sqrt{75}+2\sqrt{30} )}{30}$

$=\frac{(3\sqrt{5}+3\sqrt{5}+2\sqrt{30} )}{30}$

#SPJ2