Question

Rationalize the denominator 1/[7+3√3].​

Answer 1

1/(7+3√3)

=1/(7+3√3)*(7-3√3)/(7-3√3)

=(7-3√3)/(7+3√3)*(7-3√3)

=(7-3√3)/(7^2 - (3√3)^2)

=(7-3√3)/(49-27)

=(7-3√3)/22

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Answer 2

this is the solution.

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