rationalize the denominator;;1/7+3 root 2
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Answered by
16
Question is to Rationalize :
Solution :
= [ Multiplying by ]
=
=
=
Hence, the denominator is rationalized.
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Answered by
7
Answer:
Question is to Rationalize : \frac{1}{7+3\sqrt{2} }
7+3
2
1
Solution :
\frac{1}{7+3\sqrt{2} }
7+3
2
1
= \frac{1}{7+3\sqrt{2} }( \frac{7-3\sqrt{2}}{7-3\sqrt{2} })
7+3
2
1
(
7−3
2
7−3
2
) [ Multiplying by \frac{7-3\sqrt{2}}{7-3\sqrt{2} }
7−3
2
7−3
2
]
= \frac{7-3\sqrt{2}}{(7)^{2} -(3\sqrt{2})^{2} }
(7)
2
−(3
2
)
2
7−3
2
=\frac{7-3\sqrt{2}}{49 -18 }
49−18
7−3
2
=\frac{7-3\sqrt{2}}{31}
31
7−3
2
Hence, the denominator is rationalized.
Hope this helped you...
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