Question

rationalize the denominator 1/√7-√6​

Answer 1

☎☎ HELLO ☎☎

RATIONALISE :-

$\large= > \frac{1}{ \sqrt{7} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{7} + \sqrt{6} }$

$\large= > \frac{ \sqrt{7} + \sqrt{6} }{1}$

〽〽〽 THANK U 〽〽〽

Answer 2

TO RATIONALISE DENOMINATOR OF

$\frac{1}{ \sqrt{7} - \sqrt{6} }$

What is rationalisation?

The mathematical process in which an irrational number gets converted into Rational number without changing its value.

For converting the denominator into rational we should multiply it with such a number that the result remain same but denominator decomes rational.

ANSWER :-

$\frac{1}{ \sqrt{7} - \sqrt{6} } \\ \\ \\ = \frac{1}{ \sqrt{7} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{7} + \sqrt{6} } \\ \\ \\ = \frac{ \sqrt{7} + \sqrt{6} }{ { \sqrt{7} }^{2} - { \sqrt{6} }^{2} } \\ \\ \\ = \frac{ \sqrt{7} + \sqrt{6} }{7 - 6} \\ \\ \\ = \boxed{ \sqrt{7} + \sqrt{6} }$

[ANS]

The identity used above is :-

(a+b)(a-b) = a^2 - b^2