rationalize the denominator 1 by root 7 minus root 6
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Answered by
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Hi ,
1/( √7 - √6 )
= ( √7 + √6 )/[ (√7 - √6 )(√7 + √6 ) ]
= ( √7 + √6 )/ [ ( √7 )² - ( √6 )² ]
= ( √7 + √6 )/ ( 7 - 6 )
= √7 + √6
I hope this helps you.
: )
1/( √7 - √6 )
= ( √7 + √6 )/[ (√7 - √6 )(√7 + √6 ) ]
= ( √7 + √6 )/ [ ( √7 )² - ( √6 )² ]
= ( √7 + √6 )/ ( 7 - 6 )
= √7 + √6
I hope this helps you.
: )
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