rationalize the denominator 1 by root 7 + root 6 minus 3
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1/( √7 - √6 -3)
= ( √7 + √6-√3 )/[ (√7 - √6 )(√7 + √6-√3 ) ]
= ( √7 + √6 )/ [ ( √7 )² - ( √6 )²-√3 ]
= ( √7 + √6 )/ ( 7 - 6-3 )
= √7 + √6 +√3
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= ( √7 + √6-√3 )/[ (√7 - √6 )(√7 + √6-√3 ) ]
= ( √7 + √6 )/ [ ( √7 )² - ( √6 )²-√3 ]
= ( √7 + √6 )/ ( 7 - 6-3 )
= √7 + √6 +√3
hope it helps:)
mark as brain list
T!—!ANKS!!!
jagwinder:
it is wrong. please again read the question
check the answer now...
hop it helps
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