Question

rationalize the denominator 1 by root 7 + root 6 minus 3​

Answer 1

$\frac{1}{ \sqrt{7} + \sqrt{6} - 3 } \\ = \frac{1}{ \sqrt{7} + \sqrt{6} - 3 } \times \frac{ \sqrt{7} - \sqrt{6} + 3}{\sqrt{7} - \sqrt{6} + 3} \\ = \frac{\sqrt{7} - \sqrt{6} + 3}{7 - 6 - 3} \\ = \frac{\sqrt{7} - \sqrt{6} + 3}{2}$

This is the answer....!!!!