Question

rationalize the denominator 1 by root3 +root2

Answer 1

(√3-√2)/(√3+√2)(√3-√2)
(√3-√2)/(3-2)
(√3-√2)/1 = √3-√2

Answer 2

Hey Mate

your answer is ---


$\frac{1}{ \sqrt{3} + \sqrt{2} } = \frac{ \sqrt{3} - \sqrt{2} }{( \sqrt{3} + \sqrt{2} )( \sqrt{3} - \sqrt{2}) } \\ \\ = \frac{ \sqrt{3} - \sqrt{2} }{ { \sqrt{3} }^{2} - { \sqrt{2} }^{2} } \\ \\ = \frac{ \sqrt{3} - \sqrt{2} }{3 - 2} = \frac{ \sqrt{3} - \sqrt{2} }{1} \\ \\ = \sqrt{3} - \sqrt{2}$


Hope it helps you