Question

rationalize the denominator 1/ root 3 - root 2​

Answer 1

$\frac{1}{ \sqrt{3} - \sqrt{2} } = \frac{1 \times ( \sqrt{3} + \sqrt{2}) }{( \sqrt{3} - \sqrt{2}) \times ( \sqrt{3} + \sqrt{2} ) }$

$= \frac{ \sqrt{3} + \sqrt{2} }{ {( \sqrt{3} )}^{2} - { (\sqrt{2}) }^{2} } = \frac{ \sqrt{3} + \sqrt{2} }{3 - 2} = \frac{ \sqrt{3} + \sqrt{2} }{1} = \sqrt{3} + \sqrt{2}$

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