rationalize the denominator 1/root 7 +root 6- root 13
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1/√7+√6-√13
=1*(√7+√6)+√13/(√7+√6)-√13*(√7+√6)+√13
=√7+√6+√13/(√7)²+(√6)²+2(√7)(√6)-(√13)²
=√7+√6+√13/7+6+2√42-13
=√7+√6+√13/2√42
=
=1*(√7+√6)+√13/(√7+√6)-√13*(√7+√6)+√13
=√7+√6+√13/(√7)²+(√6)²+2(√7)(√6)-(√13)²
=√7+√6+√13/7+6+2√42-13
=√7+√6+√13/2√42
=
mudgaldarthsk00:
solve completely. it can be rationalized again
sorry to say that this solving of half question is not good
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