Math, asked by pinalrangrej4529, 3 months ago

rationalize the denominator 1 upon 2 +root 3​

Answers

Answered by aasheearora404
6

Answer:

2 -  \sqrt{3}

Step-by-step explanation:

 \frac{1}{2 +  \sqrt{3} }

when \: we \: perform \: rationalisation \: we \: divide \: and \: multiply \: the \: denominator \: with \: opposit \: sign

\frac{1}{2 +  \sqrt{3} }  \times  \frac{2 -  \sqrt{3} }{2 -  \sqrt{3} }

 \frac{2 -  \sqrt{3} }{ {2}^{2 - 3} }

 \frac{2 -  \sqrt{3} }{4 - 3}

 \frac{2 -  \sqrt{3} }{1}

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Answered by Aurora40
5

Answer:

2-√3

1/2+√3

= 1/2+√3---1/2-√3

on solving you will get

2-√3

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