Math, asked by ayushpathak8813, 10 months ago

rationalize the denominator 1 upon 7 + under root 2​

Answers

Answered by kartikshimar195
3

Here's your answer

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1 \div \sqrt{7 - 2 } \\ rationalising \: the \: denominator \\

1/√7-2 x √7+2 /√7+2

= √7+2 / (√7)²-(2)²

= √7+2 / 7-4

= √7+2/ 3 is the answer.

# Hope it helps #


Pythagaros: √7 + 2 nhi 7 + √2 hoga
kartikshimar195: Sorry my mistake
kartikshimar195: You can delete my answer
Answered by shreejl
0

Answer:

Step-by-step explanation:

1/7+√2×7-√2/7-√2

1(7-√2)/(7+√2)(7-√2)

7-√2/7^2-(√2)^2

7-√2/49-2

7-√2/47


Pythagaros: 49-2 = 47 hota hai yr
shreejl: Ops sorry
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