rationalize the denominator 1 upon 7 + under root 2
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Here's your answer
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1 \div \sqrt{7 - 2 } \\ rationalising \: the \: denominator \\
1/√7-2 x √7+2 /√7+2
= √7+2 / (√7)²-(2)²
= √7+2 / 7-4
= √7+2/ 3 is the answer.
# Hope it helps #
Pythagaros:
√7 + 2 nhi 7 + √2 hoga
Answered by
0
Answer:
Step-by-step explanation:
1/7+√2×7-√2/7-√2
1(7-√2)/(7+√2)(7-√2)
7-√2/7^2-(√2)^2
7-√2/49-2
7-√2/47
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