Question

rationalize the denominator 1 upon root 2 + root 3​

Answer 1

$\huge\tt{AnsweR}$

$\sf = \frac{1 }{2 \sqrt{3} } \\ \sf = \frac{1}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ \sf = \frac{2 - \sqrt{3} }{2 {}^{2} - ( \sqrt{3)} {}^{2} } \\ \sf = \frac{2 - \sqrt{3} }{4 - 3} \\ \sf = \frac{2 - \sqrt{3} }{1} \sf \\ \sf = 2 - \sqrt{3}$