Question

rationalize the denominator 1 upon root 7 minus 2​

Answer 1

$\frac{1}{ \sqrt{7} - 2} = \frac{1}{\sqrt{7} - 2 } \times \frac{ \sqrt{7 } + 2}{ \sqrt{7} + 2 }$
$= \frac{ \sqrt{7} + 2 }{( \sqrt{7} {}^{2} - 2 ^{2} )}$
by the formula of
$a {}^{2} - b {}^{2} = (a + b)(a - b)$
$= \frac{ \sqrt{7} + 2}{7 - 4 }$
$\frac{ \sqrt{7} + 2 }{3}$
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Answer 2

Answer:

root 7-2/5

Step-by-step explanation: