English, asked by omkar141, 1 year ago

rationalize the denominator 1 upon under root 7 minus under root 6

Answers

Answered by Panzer786
17
Hii friend,

1/✓7 - ✓6

=> 1/✓7 - ✓6 × ✓7+✓6/✓7+✓6

=> 1(✓7+✓6)/(✓7-✓6)(✓7+✓6)

=> (✓7+✓6)/(✓7)² - (✓6)²

=> ✓7 + ✓6 / 7-6

=> ✓7 + ✓6/1

=> ✓7+✓6....Ans...



HOPE IT WILL HELP YOU..... :-)

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Answered by Anonymous
4
ⓗⓔⓨ ⓕⓡⓘⓔⓝⓓ



 \frac{1}{ \sqrt{7}  -  \sqrt{6} }



 \frac{1}{ \sqrt{7} -  \sqrt{6}  }  \times  \frac{ \sqrt{7}  +  \sqrt{6} }{ \sqrt{7}  +  \sqrt{6} }



 \frac{ \sqrt{7}  +  \sqrt{6}  }{1}


=>
 \sqrt{7}  +  \sqrt{6}




Hope it helps you



 <marquee > prabhudutt
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