Math, asked by bhavsarom21, 8 months ago

Rationalize the denominator
1
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V7-V6​

Answers

Answered by raide153
7

Answer:

 \frac{ \sqrt{1} }{ \sqrt{7} -  \sqrt{6}  }

 =  \frac{ \sqrt{7} -  \sqrt{6}  }{7 - 6}

 =  \frac{ \sqrt{7} -  \sqrt{6}  }{1}

 =  \sqrt{7} -  \sqrt{6} }

Answered by anindyaadhikari13
11

 \frac{1}{ \sqrt{7}  -  \sqrt{6} }

 =  \frac{1 \times ( \sqrt{7}  +  \sqrt{6} )}{( \sqrt{7}  -  \sqrt{6} )( \sqrt{7} +  \sqrt{6} ) }

 =  \frac{ \sqrt{7}  +   \sqrt{6} }{( \sqrt{7})^{2} - ( \sqrt{6})^{2}   }

 =  \frac{ \sqrt{7} +  \sqrt{6}}{7 - 6}

 =  \frac{ \sqrt{7}  +  \sqrt{6} }{1}

 =  \sqrt{7}  +  \sqrt{6}

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