Math, asked by bhattada1909, 4 months ago

rationalize the denominator 10/√3+1​

Answers

Answered by ujjwalVishwakarma99
0

 \frac{10}{ \sqrt{3} + 1 }

Multiplying both denominator and numerator by √3-1 to rationalise the number.

 \frac{10}{ \sqrt{3} + 1 }  \times  \frac{ \sqrt{3} - 1 }{ \sqrt{3}  - 1}

 =  \frac{10( \sqrt{3} - 1) }{( \sqrt{3} + 1)( \sqrt{3}   - 1)}

 =  \frac{10( \sqrt{3 }  - 1)}{3 - 1}

 = 5( \sqrt{3}  - 1)

Similar questions