Question

Rationalize the denominator
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Answer 1

Answer:

❤️ Hey mate ❤️

Check attachment.......

Answer 2

$\dfrac{3 \: + \: \sqrt{2} }{3 \: - \: \sqrt{2} }$

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• We have to rationalize the denomination.

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=> $\dfrac{3 \: + \: \sqrt{2} }{3 \: - \: \sqrt{2} }$

Rationalize it..

=> $\dfrac{3 \: + \: \sqrt{2} }{3 \: - \: \sqrt{2} }$ × $\dfrac{3 \: + \: \sqrt{2} }{3 \: + \: \sqrt{2} }$

(a + b) (a + b) = a² + b² + 2ab

(a - b) (a + b) = a² - b²

=> $\dfrac{(3)^{2} \: + \: (\sqrt{2})^{2} \: + \: 2(3)( \sqrt{2} ) }{ {(3)}^{2} \: - \: (\sqrt{2})^{2} }$

=> $\dfrac{9 \: + \: 2 \: + \: 6\sqrt{2} }{ 9\: - \: 2}$

=> $\dfrac{11 \: + \: 6\sqrt{2} }{ 7}$

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$\dfrac{11 \: + \: 6\sqrt{2} }{ 7}$

____________ [ ANSWER ]

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