Math, asked by reenajaswal472, 9 months ago

rationalize the denominator 14 over under root 3 minus under root 5​

Answers

Answered by arorakartik070205
0

Answer:

-7√3-7√5

Step-by-step explanation:

14/(√3-√5)

=14/(√3-√5)*√3+√5/√3+√5

=14√3+14√5/3-5

=14√3+14√5/-2

= -2(-7√3-7√5)/-2

= -7√3-7√5

Answered by AAXY6
0

Answer:

4

Step-by-step explanation:

14/3-√5

(14/3-√5)* 3+√5

= [ 14 * ( 3-√5) / ( 3²- √5²) ]          [ (a+b) (a-b) = a² - b² ]

= 42-√205/ 9-5

= 42-√205/ 4

Therefore the denominator is 4

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