Question

rationalize the denominator -

16/(√41+5)​

Answer 1

Answer:

$\frac{16}{(\sqrt{41} + 5) }$

$\frac{16}{( \sqrt{41} + 5) } \times \frac{ \sqrt{41} - 5 }{ \sqrt{41} - 5 }$

$\frac{ \sqrt{41} \times 5 \times 16}{( { \sqrt{41})}^{2} - {(5)}^{2} }$

$\frac{ \sqrt{41} \times 80}{41 - 25}$

$= \frac{80 \sqrt{41} }{16}$

Answer 2

Answer:

16/(√41+5)*(√41-5)/(√41-5)=16(√41-5)/(√41+5)(√41-5)

→16(√41-5)/(41-25)=16(√41-25)/16=(√41-5)/1

Step-by-step explanation: