Question

Rationalize the denominator.... ​

Answer 1

Answer:yr solution is here.

Answer 2

ANSWER:

• The value of the above expression = (√7+√6)

GIVEN:

$\dfrac{1}{ \sqrt{7} - \sqrt{6} }$

TO FIND:

• The value of above expression.

SOLUTION:

$= \dfrac{1}{ \sqrt{7} - \sqrt{6} } \\ \\ = \frac{1}{ \sqrt{7} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{7} + \sqrt{6} } \\ \\ = \frac{( \sqrt{7} + \sqrt{6}) }{( \sqrt{7} - \sqrt{6} )( \sqrt{7} + \sqrt{6} )} \\ \\ = \frac{ \sqrt{7} + \sqrt{6} }{( \sqrt{7} ) {}^{2} - ( \sqrt{6}) {}^{2} } \\ \\ = \frac{ \sqrt{7} + \sqrt{6} }{7 - 6} \\ \\ = \frac{ \sqrt{7} + \sqrt{6} }{1} \\ \\ = \sqrt{7} + \sqrt{6}$

• The value of the above expression = (√7+√6)

NOTE:

some important formulas

• (a+b)(a-b) = a²-b²
• (a+b)² = a²+b²+2ab
• (a-b)² = a²+b²-2ab