Question

rationalize the denominator 2√3-√2
________
2√2+3√3​

Answer 1

Answer:

Rationalization of

(2√3-√2) ÷(2√2+3√3)

= (2√3-√2)*(2√2-3√3)÷(2√2+3√3)*(2√2-3√3)

= (4√6+18-4-3√6)÷(8-27)

= (√6+14)÷(-19)

= -(14+√6)÷(19)