Question

rationalize the denominator √2-√3/√2+√3=​

Answer 1

$\frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \\ = \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} } \\ = \frac{( { \sqrt{2} - \sqrt{3} })^{2} }{2 - 3} \\ = \frac{(2 + 3 - 2 \sqrt{6}) }{ - 1} \\ = - 5 + 2 \sqrt{6}$

Answer 2

Hello?

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