Math, asked by sumaira55, 7 months ago

rationalize the denominator 2√3+3√2/2√3-3√2 ​

Answers

Answered by satyamsingh02003
0

Ans:- (2√3 + 3√2) / (2√3 - 3√2)

= (2√3 + 3√2)(2√3 + 3√2) / (2√3 - 3√2)(2√3 + 3√2)

= (12 + 6√6 + 6√6 + 18) / (12 + 6√6 - 6√6 - 18)

= (12 + 12√6 + 18) / (12 - 18)

= (12 + 12√6 + 18) / -6

= -2 -2√6 - 3

= -(2 + 2√6 + 3)

here is your answer

hope it will help you

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