rationalize the denominator 2√3+3√2/2√3-3√2
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Ans:- (2√3 + 3√2) / (2√3 - 3√2)
= (2√3 + 3√2)(2√3 + 3√2) / (2√3 - 3√2)(2√3 + 3√2)
= (12 + 6√6 + 6√6 + 18) / (12 + 6√6 - 6√6 - 18)
= (12 + 12√6 + 18) / (12 - 18)
= (12 + 12√6 + 18) / -6
= -2 -2√6 - 3
= -(2 + 2√6 + 3)
here is your answer
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