Question

rationalize the denominator 2/√5-√2​

Answer 1

$\huge \fbox \red{answer}$

We rationalize the denominator,

We rationalize the denominator, 5

We rationalize the denominator, 5

We rationalize the denominator, 5 +

We rationalize the denominator, 5 + 3

We rationalize the denominator, 5 + 3

We rationalize the denominator, 5 + 3

We rationalize the denominator, 5 + 3 2

We rationalize the denominator, 5 + 3 2

We rationalize the denominator, 5 + 3 2 ×

We rationalize the denominator, 5 + 3 2 × 5

We rationalize the denominator, 5 + 3 2 × 5

We rationalize the denominator, 5 + 3 2 × 5 −

We rationalize the denominator, 5 + 3 2 × 5 − 3

We rationalize the denominator, 5 + 3 2 × 5 − 3

We rationalize the denominator, 5 + 3 2 × 5 − 3

We rationalize the denominator, 5 + 3 2 × 5 − 3 5

We rationalize the denominator, 5 + 3 2 × 5 − 3 5

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 −

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 =

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−3

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32(

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 −

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3 )

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3 )

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3 )

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3 ) =

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3 ) = 5

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3 ) = 5

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3 ) = 5 −

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3 ) = 5 − 3

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3 ) = 5 − 3

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3 ) = 5 − 3

We rationalize the denominator, 5 + 3 2 × 5 − 3 5 − 3 = 5−32( 5 − 3 ) = 5 − 3 ∴ Value of m=5