Question

Rationalize the denominator 2/(√5+√3)+1/(√3+√2)-3/(√5+√2)

Answer 1

Answer:

0

Step-by-step explanation:

2/(√5+√3)+1/(√3+√2)-3/(√5+√2)

First, let's rationalize each term:

• 2/(√5+√3)= 2(√5-√3)/(√5-√3)(√5+√3)= 2(√5-√3)/2=√5-√3

Following ones are similar to one above:

• 1/(√3+√2)= ...=√3-√2

• 3/(√5+√2)= ...=√5-√2

The sum is now:

• 2/(√5+√3)+1/(√3+√2)-3/(√5+√2)= √5-√3+√3-√2-(√5-√2)=0

The answer is zero