Math, asked by a64hansika10vrm, 7 months ago

rationalize the denominator 2/√7 - √5​

Answers

Answered by MoodyCloud
34

 =  \frac{2}{ \sqrt{7}  -  \sqrt{5}}  \\  \\ \frac{2}{ \sqrt{7}  -  \sqrt{5}}   \times  \frac{ \sqrt{7}  +  \sqrt{5} }{ \sqrt{7}  +  \sqrt{5} }  \\  \\   = \frac{2 \sqrt{7}  + 2 \sqrt{5} }{  {( \sqrt{7}) }^{2} -  {( \sqrt{5}) }^{2}   }  \\  \\   = \frac{2 \sqrt{7}  + 2 \sqrt{5} }{7 - 5}  \\  \\  =  \frac{2 \sqrt{7} + 2 \sqrt{5}  }{2}  \\

 =  \sqrt{7}  + 2 \sqrt{5}

Answered by rkushwaha8127
3

Answer:

hence answervare √7+√5 are ✅ correct

for solution see picture ️

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