Math, asked by gollapallihoneyv, 9 months ago

rationalize the denominator 2 by root 7 + root 6​

Answers

Answered by harryoms
1

Answer:

rationalize the denominator 2 by root 7 + root 6

= 2( √7 - √6)

Attachments:
Answered by atahrv
5

Answer:

\large\boxed{\star\:\:2\sqrt{7}-2\sqrt{6}\:\:\star}

Step-by-step explanation:

To Rationalize:-

\frac{2}{\sqrt{7}+\sqrt{6} }

Formula Applied:-

(a-b)×(a+b)=(a)²-(b)²

Rationalization:-

\implies\frac{2}{\sqrt{7}+\sqrt{6} }

\implies\frac{(2)\times(\sqrt{7}-\sqrt{6})}{(\sqrt{7}+\sqrt{6})\times(\sqrt{7}-\sqrt{6}) }

\implies\frac{(2)\times(\sqrt{7}-\sqrt{6})}{(\sqrt{7})^2-(\sqrt{6})^2  }

\implies\frac{2\sqrt{7}-2\sqrt{6}}{7-6}

\implies\frac{2\sqrt{7}-2\sqrt{6}}{1}

\implies\boxed{2\sqrt{7}-2\sqrt{6}}

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