Question

rationalize the denominator 2 root 3 + 3 root 2 by 6 root 2 minus 5 root 3

Answer 1

I hope it helps you
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Answer 2

Hi...✌

Here is your answer...☺

On rationalising
we get,

$\frac{2 \sqrt{3 } + 3 \sqrt{2} }{6 \sqrt{2} - 5 \sqrt{3} } \times \frac{6 \sqrt{2} + 5 \sqrt {3} }{6 \sqrt{2} + 5 \sqrt{3} } \\ \\ = \frac{12 \sqrt{6} + 30 + 36 + 15 \sqrt{6} }{ {(6 \sqrt{2}) }^{2} - {(5 \sqrt{3} )}^{2} } \\ \\ = \frac{27 \sqrt{6} + 66 }{72 - 75} \\ \\ = \frac{27 \sqrt{6} + 66 }{ - 3} \\ \\ = - 9 \sqrt{6} -22$

Thank you ⭐