Math, asked by n05601, 7 months ago

rationalize the denominator 2+root3/2-root3​

Answers

Answered by lepordgamingyt
1

Answer:

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Answered by ramandhamija
2

Step-by-step explanation:

2+√3/2-√3

BY RATIONALIZING WE GET

2+3× 2+3/2-3×2+3

= (2+3)²/2²-3² as (a+b) (a-b) = a²-b²

= (2+3)²/4-3

(2+3)²/1 or it can be written as

(2+3)²

= 4+(3)² +43

= 4+3+43

= 7+43

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