Question

rationalize the denominator 25/√40 - √80 if √5 = 2.236 , √10 = 3.162 plzzz answer this question I will mark as brainliest

Answer 1

here is your answer


your answer is 149. 156

Answer 2

$\huge\underline\mathfrak{Answer:}$

Given:

$\frac{25}{ \sqrt{40 } - \sqrt{80} } = \frac{25}{ \sqrt{40} - \sqrt{80} } \times \frac{ \sqrt{40} + \sqrt{80} }{ \sqrt{40} + \sqrt{80 } } \\ \\ = \frac{25 \times ( \sqrt{40} + \sqrt{80}) }{( \sqrt{40}) {}^{2} - ( \sqrt{80} ) {}^{2} } \\ \\ = \frac{25 \times ( \sqrt{4 \times 10} + \sqrt{16 \times 5} } {40 - 80} \\ \\ = \frac{25 \times (2 \sqrt{10} + 4 \sqrt{5}) }{ - 40} \\ \\ = \frac{ - 5}{8} (2 \sqrt{10} + 4 \sqrt{5}) \\ \\ = \frac{ - 5}{8} (2 \times 3.162 + 4 \times 2.23) \\ \\ = \frac{ - 5}{8} (6.324 + 8.944) \\ \\ = \frac{ - 5}{8} (15.268) \\ \\ = - 5 \times 1.9085$

$\bold{\large{\boxed{\sf{\purple{Ans:-9.5425}}}}}$