Math, asked by lovepreetsingh66, 10 months ago

rationalize the denominator:-√3+1/√3-1​

Answers

Answered by Anonymous
2

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 \frac{ \sqrt{3} + 1 }{ \sqrt{3} - 1 }

 \frac{ \sqrt{3} + 1 }{ \sqrt{3} - 1 } \times   \frac{ \sqrt{3} + 1 }{ \sqrt{3}  + 1}

 \frac{ {( \sqrt{3} + 1) }^{2} }{ { \sqrt{3}^{2} -   {1}^{2}  } }

 \frac{ {( \sqrt{3} + 1) }^{2} }{3 - 1}

 \frac{ {( \sqrt{3} + 1) }^{2} }{2}

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