Question

rationalize the denominator:3/2-√2=a+b√2​

Answer 1

Answer:

$\frac{6+3\sqrt{2} }{2 }$

Step-by-step explanation:

$\frac{3}{2-\sqrt{2} } =a+b\sqrt{2}$

$\frac{3}{2-\sqrt{2} } *\frac{2+\sqrt{2} }{2+\sqrt{2} }$

=$\frac{6+3\sqrt{2} }{2^{2}-\sqrt{2} ^{2} } }$

=$\frac{6+3\sqrt{2} }{4-2 }$

=$\frac{6+3\sqrt{2} }{2 }$