Question

rationalize the denominator 3√ 2/7-√6​

Answer 1

Answer:

3√2/7-√6

3√2(7+√6)/(7-√6) (7+√6)

21√2+3√12/(7) ^2-(√6) ^2

21√2+3√12/43

Answer 2

$\implies \sf \dfrac{ 3\sqrt{2} }{7 - \sqrt{6} }$

$\implies \sf \dfrac{ 3\sqrt{2} }{7 - \sqrt{6} } \times \dfrac{7 + \sqrt{6} }{7 + \sqrt{6} }$

$\implies \sf \dfrac{ 21\sqrt{2} + 3 \sqrt{12} }{ {7}^{2} - \sqrt{{6}^{2} } }$

$\implies \sf \dfrac{ 21\sqrt{2} + 6 \sqrt{3} }{ 49 - 6 }$

$\implies \sf \dfrac{ 21\sqrt{2} + 6 \sqrt{3} }{ 43}$