Question

rationalize the denominator 3/2-root 3​

Answer 1

Answer:

6 + 3√3

Step-by-step explanation:

Given that ;

$\dfrac{3}{2 - \sqrt{3} }$

To rationalise the denominator, multiply the numerator and denominator by the rationalising factor i.e., (2 + √3).

$\frac{3}{2 - \sqrt{3} } \\ \\ \frac{3}{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } \\ \\ \frac{3(2 + \sqrt{3}) }{(2) {}^{2} - ( \sqrt{3}) {}^{2} }$

[Because, (a + b)(a - b) = a² - b²]

$\implies \frac{6 + 3 \sqrt{3} }{4 - 3} \\ \\ \implies \frac{6 + 3 \sqrt{3} }{1} \\ \\ \implies \bf 6 + 3 \sqrt{3}$

Hence, the answer is 6 + 3 √3.

Answer 2

hope this helps you☺️☺️☺️