Question

rationalize the denominator √3 / √3+√2-√5​

Answer 1

Answer:

$\sqrt{3} \div \sqrt{3} + \sqrt{2} - \sqrt{5 } \\ = \sqrt{3} \div \sqrt{3} + \sqrt{6 } \div \sqrt{3} - \sqrt{15} \div \sqrt{3} \\ = \sqrt{ - 6} \div \sqrt{3 } \\ = \sqrt{ - 2} \div \sqrt{1} \\ = \frac{ + }{ - } \sqrt{2}$