Math, asked by joeldebbarma123, 10 months ago

rationalize the denominator √3/4√3-5√2​

Answers

Answered by divyahada3
0

Step-by-step explanation:

so for rationalising it we have to multiply it by

1 which can be written as = 4root3 + 5root2 / 4root3 + 5root2

so whe we multiply it with

(root3 / 4root3- 5root2 ) × ( 4root3+5root2/4root3+5root2)

= root3 (4root3+5root2)

(4root3)^2- (5root2)^2

= 12+5root6

48 - 50

= 12+5root6 will be its rationalised form of denom

-2

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