Math, asked by lakshya5146, 1 month ago

rationalize the denominator 3÷√5 +√2​

Answers

Answered by deepagupta12
1

Answer:

 \frac{3}{ \sqrt{5}   +  \sqrt{2} }

 =  \frac{3}{ \sqrt{5}  +  \sqrt{2} }  \times  \frac{ \sqrt{5}   -  \sqrt{2} }{ \sqrt{5} -  \sqrt{2}  }

  =   \frac{3( \sqrt{5}  -  \sqrt{2} )}{ ({ \sqrt{5} }^{2} )  -  { (\sqrt{2} }^{2} )}

 =  \frac{3( \sqrt{5}  -  \sqrt{2} )}{5 - 2}

 =  \frac{3( \sqrt{5} -  \sqrt{2})  }{3}

 =  \sqrt{5}  -  \sqrt{2}

Step-by-step explanation:

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