Question

rationalize the denominator √3/√6+√2​

Answer 1

Step-by-step explanation:

$\frac{ \sqrt{3} }{ \sqrt{6 } + \sqrt{2} } = \frac{ \sqrt{6} - \sqrt{2} }{ \sqrt{6} - \sqrt{2} } \\ \frac{3 \sqrt{2} - \sqrt{6} }{6 - 2} \\ \frac{3 \sqrt{2} - \sqrt{6} }{4}$