Math, asked by vedantthakur2006, 7 months ago

rationalize the denominator 3/√6-√7​

Answers

Answered by Anjali5869
13

Answer:

The answer is -3(√6+√7)

Step-by-step explanation:

  • 3/√6-√7 × √6+√7/ √6+√7
  • = 3√6 + 3√7 / (√6)²- (√7)²
  • Identity (a+b) (a-b) = ( a²- b² )
  • 3(√6 + √7) / (6-7)
  • = 3(√6+√7) / -1
  • = -3(√6+√7)

In rationalization the sign of the denominator change when it went in numerator

for ex. . + sign changes into -

and - sign changes into +

Answered by amitnrw
1

Given : 3/(√6 - √7)

\dfrac{3}{ \sqrt{6} - \sqrt{7} }

To Find : rationalize the denominator

Solution:

\dfrac{3}{ \sqrt{6} - \sqrt{7} }

Denominator is √6 - √7

Rationalizing factor will be √6  + √7

Multiply and divide by Rationalizing factor

=\dfrac{3}{ \sqrt{6} - \sqrt{7} } \times\dfrac{\sqrt{6} + \sqrt{7}}{ \sqrt{6} + \sqrt{7} }

Using identity  (a + b)(a - b)  = a² - b²

and (√a)² = a

=\dfrac{3(\sqrt{6} + \sqrt{7})}{  6 -7 }

=\dfrac{3(\sqrt{6} - \sqrt{7})}{  -1 }

= -3(\sqrt{6} + \sqrt{7})

Hence Answer is - 3(√6 + √7)

Learn More:

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