Question

rationalize the denominator 3 divided by root 3 + root 2 minus 3 root 2 divided by root 6 + root 3 + 4 root 3 / root 2 + 6

Answer 1

3/√3 +( √2 -3√2)/(√6 +√3 ) + 4√3/(√2 + 6)

=3/√3 -2√2/(√6+√2) +4√3/(√2+ 6)

=3√3/3 -2√2(√6-√2)/4 + 4√3(6-√2)/34

= √3 - (√3 -1) + 4√3( 6 -√2)/34

= 1 + ( 24√3 - 4√6)/34