Question

rationalize the denominator 3 minus 2 root 2 / 3 + 2 root 2 answer

Answer 1

$Hey \: There$!!

$\frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} }$

$= \frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} } \times \frac{3 - 2\sqrt{2} }{3 - 2 \sqrt{2} }$

$= \frac{ {(3 - 2 \sqrt{2} ) }^{2} }{ ({3})^{2} + ( {2 \sqrt{2}) }^{2} }$

$= \frac{9 - 12 \sqrt{2} + 8 }{9 + 8}$

$= \frac{17 - 12 \sqrt{2} }{17}$

$Hope \: my \: ans.s \: is \: satisfactory$(^-^)

Answer 2

Hey!
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Question :-

3 - 2√2 ÷ 3 + 2√2

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Solution :-

(3 - 2√2 ÷ 3 + 2√2) × (3 - 2√2 ÷ 3 - 2√2)

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•Identity which is used in denominator :-

= a² - b² = (a + b) (a - b)

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= (3 - 2√2)² ÷ (3)² + (2√2)²

= 9 - 12√2 + 8 ÷ 9 + 8

= 17 - 12√2 ÷ 17


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Regards :)

Cybary

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