Math, asked by dineshyadav738, 3 months ago

rationalize the denominator ​

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Answered by vipashyana1
1

Answer:

i) \frac{3}{ \sqrt{5} }  =  \frac{3}{ \sqrt{5} }  \times  \frac{ \sqrt{5} }{ \sqrt{5} }  =  \frac{3 \sqrt{5} }{5}  \\ ii) \frac{6}{9 \sqrt{3} }  =  \frac{6}{9 \sqrt{3} } \times  \frac{ \sqrt{3} }{ \sqrt{3} } =  \frac{6 \sqrt{3} }{9 \times 3}  =  \frac{6 \sqrt{3} }{27}   =  \frac{2 \sqrt{3} }{9}   \\ iii) \frac{5}{ \sqrt{7} }  =  \frac{5}{ \sqrt{7} }  \times  \frac{ \sqrt{7} }{ \sqrt{7} }  =  \frac{5 \sqrt{7} }{7}

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