Question

Rationalize the denominator
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Answer 1

Answer:

16.

Step-by-step explanation:

Given:

$\frac{3 + \sqrt{7} }{3 - \sqrt{7} } + \frac{3 - \sqrt{7} }{3 + \sqrt{7} }$

Solution:

$\frac{3 + \sqrt{7} }{3 - \sqrt{7} } \times \frac{3 + \sqrt{7} }{3 + \sqrt{7} } + \frac{3 - \sqrt{7} }{3 + \sqrt{7} } \times \frac{3 - \sqrt{7} }{3 - \sqrt{7} } \\ = > \frac{(3 + { \sqrt{7} )}^{2} }{( {3)}^{2} - ( {3)}^{2} } + \frac{(3 - { \sqrt{7}) }^{2} }{ {(3)}^{2} - ( { \sqrt{7} )}^{2} } \\ = > \frac{9 + 7 + 2 \times 3 \times \sqrt{7} }{9 - 7} + \frac{9 + 7 - 2 \times 3 \times \sqrt{7} }{9 - 7} \\ = > \frac{16 + 6 \sqrt{7} }{2} + \frac{16 - 6 \sqrt{7} }{2} \\ = > \frac{16 + 6 \sqrt{7} + 16 - 6 \sqrt{7} }{2} \\ = > \frac{32}{2} \\ = > 16 \: \ans. \\ {}^{ \please \: mark \: me \: brainlist \: ans.}$

Answer 2

Answer:

16 is your correct answer.