Question

rationalize the denominator​

Answer 1

Answer:

5-2√6

Step-by-step explanation:

$\frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\ = \frac{ (\sqrt{3} - \sqrt{2} ) {}^{2} }{ (\sqrt{3}) {}^{2} - (\sqrt{2} ) {}^{2} } \\ = \frac{( \sqrt{3}) {}^{2} - 2 \times \sqrt{3} \times \sqrt{2} + ( \sqrt{2} ) {}^{2} }{ 3 - 2 }$

$\frac{3 - 2 \sqrt{6} + 2}{1} = 5 - 2 \sqrt{6}$

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Answer 2

5-2√6

$\red{Hope \ it \ helps}$